An intelligent trader travels from one place to another with 3 sacks having 30 coconuts each. No sack can hold more than 30 coconuts. On the way, he passes 30 check points. At each check point, he has to give one coconut for every sack he is carrying. What is the maximum number of coconuts that he can have with him at the end of his journey?

Why this works

This riddle cleverly plays with the concept of managing resources and reducing the number of sacks to minimize losses. Initially, the trader has 3 sacks, so he pays 3 coconuts at each of the first 10 checkpoints, which takes out the first sack completely (30 coconuts - 30 coconuts = 0). Then, with just 2 sacks left, he pays 2 coconuts at each of the next 15 checkpoints, depleting the second sack (30 - 30 = 0). Finally, with only 1 sack remaining, he only needs to pay 1 coconut at each of the last 5 checkpoints, leaving him with 25 coconuts. The riddle teaches us about strategic thinking and resource management in a fun and engaging way!