There are 12 kids in a classroom. 6 kids are wearing socks and 4 are wearing shoes. 3 kids are wearing both. How many are bare feet?

Why this works

To solve this riddle, we need to account for the total number of kids and how they are divided among those wearing socks, shoes, or both. We start with 12 kids in total. Since 3 kids are wearing both socks and shoes, we count them in both categories. So, we have: - 6 kids wearing socks (including the 3 who also wear shoes) - 4 kids wearing shoes (including the 3 who also wear socks) When we combine these two groups, we must subtract the 3 kids counted twice (those wearing both), which gives us: 6 (socks) + 4 (shoes) - 3 (both) = 7 kids who are either wearing socks or shoes. To find out how many kids are barefoot, we subtract the 7 kids who are wearing something from the total of 12 kids: 12 total kids - 7 kids with footwear = 5 kids with bare feet. This logical breakdown of the groups shows us how the answer is derived, making it clear why 5 kids are barefoot!